Selasa, 02 Oktober 2012

quis 1 (3,10,2012)kelas A

Nama :Alexandre da silva R.saldanha
Nim :11110045


1.A. Rumusnya:  y – y1 = m (x-x1)
                                Y - 5 = 2 ( x - ( - 3)
                                Y – 5 = 2 x + 6
                                Y = 2x + 6 + 5
                                 Y = 2x + 11  atau
                                 Y - 2x = 11























2.    a.   3x + 2y = 5
        b.  -4x + y = 10
Eliminasi
3x + 2y = 5
-4x + y = 10 x 2
3x +  2y = 5
-8x+2y=20     -
        -11x = 25
              X = 25
X =2,27
3x+2y=5
-8x + 2y =5
-8(2,27)+2y=5
-18,6+ 2y=5
       2y =5-18,6
       2y = 23.13/2
         Y=11.565
Subsitusi
A : 3x+2y=5
          2y = 5+3x
         Y = (5 + 3x/2)